If it's not what You are looking for type in the equation solver your own equation and let us solve it.
25x-2x^2=0
a = -2; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·(-2)·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*-2}=\frac{-50}{-4} =12+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*-2}=\frac{0}{-4} =0 $
| 40+3h=46 | | 7/5=350/x | | -30+3n=2(n+3)-2n | | 4/5x=-7/10 | | 5(10)-y=4 | | 9.8t^2-20.9t-12=0 | | 7/5=350/f | | 5(9)-y=4 | | 5(8)-y=4 | | 15x-8=12x+11 | | 5(7)-y=4 | | 5(6)-y=4 | | 39=-2(21-y)+3(y-3) | | 9=3x+6=24 | | 5(5)-y=4 | | 6(-2-3p)=-6+4(1-5p) | | 5(3)-y=4 | | 1.02g-6=0.63 | | 11(x-5)=10x+50 | | 5(4)-y=4 | | 6(3x-8)-4=6(x-2)+44 | | -2(x-5)=6(2-0.5) | | 5(0)-y=4 | | 10x-23=29+13x | | 8(x+5)+3=10x-2(x-5) | | |x|+3=15 | | 6m+9m=11m-12-7+18 | | x^2+2x−8=0 | | -3(8p+3)-2(6-17p)=3(3+3p) | | 4+5(3x−2)=-2(-x+6)-1 | | 1/5(10x-10)=5x-17 | | 5(1)-y=4 |